0=4x^2-13x+10

Solution for 0=4x^2-13x+10 equation:

0=4x^2-13x+10

We move all terms to the left:

0-(4x^2-13x+10)=0

We add all the numbers together, and all the variables

-(4x^2-13x+10)=0

We get rid of parentheses

-4x^2+13x-10=0

a = -4; b = 13; c = -10;
Δ = b2-4ac
Δ = 132-4·(-4)·(-10)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-3}{2*-4}=\frac{-16}{-8}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+3}{2*-4}=\frac{-10}{-8}
=1+1/4
$